Question 48 (Textile Engineering & Fibre Science)
A 60.5 tex yarn with an unevenness CV of 10% is produced from 0.5 tex polyester fibre. The index of irregularity of the yarn, accurate to one decimal place, will be ………………..
Given in the question–
Tex of yarn=60.5
Tex of polyester fibre=0.5
Index of irregularity of yarn=?
Index of irregularity=CV eff/CV lim
Where, n is the number of fibres in the yarn cross section
n=Tex of yarn/tex of fibre
Index of irregularity=10/9.09
Index of irregularity=1.10 (Answer)