Question 37 (Textile Engineering & Fibre Science)
A rotor with 48 mm diameter running at 90,000 rpm is producing yarn at 140 m/min. The number of doublings of fibre layers in the rotor is __96.85 : 97.05__.
Given in the question–
Diameter of rotor=48 mm
Rotational speed of rotor=90000 rpm
The number of doublings of layers in the rotor=?
TPI=Rotational speed of rotor/FRD
i.e. 1 meter have=643 turns
=643 x 3.14 x 48 x 10-3
No. of doubling of fibres layers in rotor=96.91 (Answer)