Question 35 (Textile Engineering & Fibre Science)
To obtain high molecular weight nylon-66, if 11.6g of hexamethylene diamene (molecular weight 116 g/mol) is used, then the required amount of adipic acid (molecuar weight 146 g/mol), in gram, accurate to one decimal place, is ___14.5 to 14.7____.
Given in the question–
Amount of hexamethylene diamene=11.6 gm
Molecular weight of hexamethylene diamene=116 g/mol
Molecular weight of adipic acid=146 g/mol
The required amount of adipic acid(gram)=?
Now by the chemical reaction of Nylon66 to obtain high molecular weight nylon66 ,formula:
Molecular weight of hexamethylene diamene/Amount of hexamethylene diamene=Molecular weight of adipic acid/Amount of adipic acid
116/11.6=146/Amount of adipic acid
Amount of Adipic acid=146 x 11.6/116
Amount of Adipic acid=1693.6/116
Amount of Adipic acid=14.6 gm (Answer)