Question 45 (Textile Technology & Fibre Science)
The molecular weight (M) of a polymer is determined from Mark-Houwink Equation by using coefficient K = 11.5×10−3 ml/g and exponent a = 0.73. If the measured intrinsic viscosity [η] of the solution is 6.0×102 ml/g then the value of M×10−6, (rounded off to two decimal places), is __2.70 to 3.10__.
=KMa ,where is viscosity , K is coefficient, M is molecular weight of polymer ,a is constant
As given in the question,
K=11.5×10-3 ml/g,a=0.73 and =6.0×102 ml/g
By putting these values in to the formula-
By taking log both side-
M=e14.88 , (By logarithm rule, loge m n=m loge n and loge m=n to m=en)